Convert Hz to Wavelength (m)
How to convert Hz to Wavelength (m)
To convert a frequency in Hz to its acoustic wavelength in meters, divide the speed of sound (343 m/s at 20°C) by the frequency: **λ = 343 ÷ f**. For example, a 100 Hz tone has a wavelength of 343 ÷ 100 = 3.43 meters. At 1 kHz, the wavelength is 343 ÷ 1000 = 0.343 meters (34.3 cm). At 20 Hz, the wavelength is 343 ÷ 20 = 17.15 meters. The reference speed of sound (343 m/s) assumes dry air at 20°C (68°F) at sea level; temperature and humidity affect this value slightly, but 343 is the standard acoustic engineering reference.1
Common Hz to Wavelength (m) conversions
Why wavelength matters for speaker placement
In speaker placement, wavelength is the physical size of a sound wave at a given frequency. When wavelength is comparable to or larger than a room dimension, the room boundary strongly interacts with the wave, creating the standing waves and room modes that cause uneven bass reproduction. At 40 Hz, the wavelength is 8.6 meters. A room 4.3 meters wide will have an axial mode at 40 Hz because the room is exactly half a wavelength wide. Knowing the wavelength of a problem frequency immediately tells you which room dimensions to examine for mode formation. Convert the troublesome frequency to its wavelength using the tool, then compare that wavelength to each room dimension: any dimension that equals half the wavelength, a quarter wavelength, or three-quarters of a wavelength is a candidate for producing a standing wave at that frequency.2
Wavelength and tweeter dispersion
At high frequencies, wavelength determines how narrowly a tweeter disperses sound. When the wavelength becomes shorter than the tweeter's diaphragm diameter, the driver begins to beam: concentrating output in a narrow on-axis cone rather than radiating broadly. A 1-inch (2.54 cm) tweeter dome begins to show directivity effects when the wavelength drops below approximately twice its diameter, around 5–6 kHz. At 16 kHz, the wavelength is 2.14 cm, shorter than the tweeter dome, meaning the on-axis response is significantly higher than the off-axis measurement. This is why sitting directly in front of a speaker at high frequencies produces brighter, more extended treble than an off-axis position.3
Room mode prediction before running the sweep
When bass sounds uneven at specific frequencies during a sweep, calculating whether a room axial mode is responsible takes a simple measurement and one formula. Measure your room's length, width, and ceiling height in meters, then apply f = 343 ÷ (2 × dimension) for the first axial mode on each axis. For a room 4.8 meters long, the first length mode is at 343 ÷ 9.6 = 35.7 Hz. A room 3.2 meters wide has its first width mode at 343 ÷ 6.4 = 53.6 Hz. These calculations predict exactly which low frequencies will accumulate or cancel at different positions in your room before you run a single sweep pass.
Confirming the match between calculated and measured frequencies
After calculating axial modes for all three room dimensions, run the full-range frequency sweep and listen for bass buildup or reduction at those specific frequencies. A match between a calculated mode and a sweep result confirms the room geometry is the cause. A problem frequency that does not match any axial mode is more likely a speaker port tuning, cabinet resonance, or a tangential mode (between two pairs of surfaces) that the simple formula does not cover. The Hz-to-wavelength conversion and its inverse work together: convert the room dimension to find the frequency, then verify in the sweep.4
If the sweep reveals a strong buildup at a frequency that does not match any axial mode, check for tangential modes by applying the formula f = 343 ÷ 2 × sqrt((n/L)² + (m/W)²) where n and m are integers representing the mode order on each axis. Tangential modes involve two pairs of surfaces and often appear at frequencies between the axial modes. The sweep is the only practical way to distinguish a room mode from a speaker or port issue without measurement equipment. If the problem frequency shifts when you move the speaker but not when you move the listener, it is likely a speaker boundary interaction rather than a room mode.
Speaker-to-wall distance and the quarter-wavelength rule
When a speaker is placed at a specific distance from a room boundary, the reflected sound from that wall arrives back at the speaker with a phase relationship determined by the wavelength at each frequency. At a speaker-to-wall distance equal to one quarter of the wavelength (λ/4), the reflected wave arrives 180° out of phase with the original output, producing a cancellation notch at that frequency. Using the Hz-to-wavelength conversion to find the quarter-wavelength of a problem frequency reveals the exact speaker-to-wall distance that will cause cancellation.
Using the conversion to avoid cancellation distances
For 80 Hz (wavelength 4.29 m), a quarter-wavelength is 1.07 meters. A speaker placed 1.07 meters from the rear wall will exhibit a bass cancellation near 80 Hz at some listening positions, even if the speaker measures flat in free-field conditions. Calculating the wavelength for your critical monitoring frequency and checking the speaker placement against its quarter-wavelength tells you in advance whether that distance will cause a problem.
Moving the speaker to shift the cancellation notch
If the speaker's distance to the nearest wall equals the quarter-wavelength of the crossover or subwoofer crossover frequency, moving the speaker 20 cm forward or backward shifts the cancellation notch to a different frequency. This often resolves a previously puzzling thin-sounding bass region near the crossover point. Run the Hz-to-wavelength conversion for the problem frequency, calculate the quarter-wavelength, measure your actual speaker-to-wall distance, and compare the two to determine whether placement is contributing to your sweep result.5
Try in the tool
Conversion covered by this page
100 Hz converts to 3.43 Wavelength (m) using the formula on this page. Use this figure as a reference point alongside the tool below.
Verify with the Speaker Frequency Sweep & Resonance Tester tool.
Try it in the tool ↑- 1.
"Speed of sound," en.wikipedia.org, accessed June 2026. https://en.wikipedia.org/wiki/Speed_of_sound
- 2.
"Room modes," en.wikipedia.org, accessed June 2026. https://en.wikipedia.org/wiki/Room_modes
- 3.
Paul White, "Practical Acoustic Treatment, Part 1," soundonsound.com, July 1998. https://www.soundonsound.com/techniques/practical-acoustic-treatment-part-1
- 4.
Rene Christensen, "Simulation Techniques: Room Gain," audioxpress.com, April 2024. https://audioxpress.com/article/simulation-techniques-room-gain
- 5.
Hugh Robjohns, "Q. How can I address the uneven bass response in my studio?," soundonsound.com, April 2004. https://www.soundonsound.com/sound-advice/q-how-can-address-uneven-bass-response-my-studio
At 80 Hz, wavelength = 343 ÷ 80 = 4.29 meters. This is the reason below 80 Hz is considered non-directional for most listeners: the wavelength is longer than head width by a large margin, meaning the ears cannot detect the delay difference between the two ears that enables directional hearing. CapyToolkit's Speaker Sweep lets you test that placement flexibility at the listening position. A subwoofer producing 80 Hz content can be placed anywhere in the room without affecting the perceived direction of the bass.
For a room 4 meters wide, the first axial mode occurs at 343 ÷ (2 × 4) = 42.9 Hz, where the half-wavelength equals the room width. For a 5-meter room length, the axial mode is at 343 ÷ 10 = 34.3 Hz. Calculating the axial modes for your room's three dimensions quickly identifies which low frequencies are most affected by room resonances.
The speed of sound in air is approximately 343 m/s at 20°C (68°F) at sea level. Temperature has the largest practical effect: for every 1°C increase in temperature, the speed of sound increases by about 0.6 m/s. At 30°C (86°F), the speed is approximately 349 m/s, changing the wavelength of a 100 Hz tone from 3.43 m to 3.49 m. This difference is small enough that 343 m/s is a reliable constant for most practical audio calculations.
Yes. Speakers produce a pressure maximum at solid reflective boundaries. When a speaker is placed at a distance from the wall equal to one-quarter wavelength of a specific frequency, the reflected wave arrives at the speaker with 180° phase shift, partially cancelling the direct output at that frequency. For 80 Hz (wavelength 4.29 m), a quarter-wavelength is 1.07 m, so a speaker 1 meter from the rear wall will have a bass cancellation near 80 Hz in some room configurations.
A 19-inch rack measures 0.4826 meters. The frequency whose wavelength equals this width is f = 343 ÷ 0.4826 ≈ 711 Hz. Below 711 Hz, the rack width is less than one wavelength, which means diffraction effects from the rack are most significant in the upper bass and lower midrange, making this relevant when placing equipment racks near studio monitors.
Convert Wavelength (m) to Hz
How to convert Wavelength (m) to Hz
To convert an acoustic wavelength in meters to its frequency in Hz, divide the speed of sound (343 m/s at 20°C) by the wavelength: **f = 343 ÷ λ**. For example, a 4.29-meter wavelength corresponds to 343 ÷ 4.29 ≈ 80 Hz, the standard home theatre crossover frequency. A 0.343-meter wavelength gives 343 ÷ 0.343 = 1000 Hz (1 kHz). Use this conversion when a room dimension, driver size, or distance is known and you want to find its corresponding acoustic frequency.1
Common Wavelength (m) to Hz conversions
Calculating room mode frequencies from dimensions
The most practical use of wavelength-to-frequency conversion is calculating the axial mode frequencies for your room. Measure each room dimension in meters, double it (to find the full wavelength for the lowest axial mode), then divide 343 by this value. A room 5.2 meters long has its first axial mode at 343 ÷ (5.2 × 2) = 343 ÷ 10.4 = 33 Hz. The second axial mode is at 66 Hz, the third at 99 Hz, and so on. Calculating all three axes (length, width, height) and their first few harmonics gives a complete picture of which low frequencies will be most affected by your room geometry.2
Driver size and directivity frequency limits
Knowing the wavelength-to-frequency relationship also explains speaker driver sizing. When a driver's diameter becomes larger than half the wavelength of the frequency it is reproducing, it begins to beam, dispersing sound in a narrow cone rather than broadly. A 6.5-inch woofer (16.5 cm diameter) has a half-wavelength at 343 ÷ (0.165 × 2) = 343 ÷ 0.33 = 1039 Hz. Above roughly 1 kHz, a 6.5-inch cone becomes increasingly directional. This is why 6.5-inch woofers in most speaker designs are crossed over to a tweeter between 1 and 3 kHz; the tweeter provides broader dispersion in the range where the woofer's directivity becomes problematic.3
Driver size and beaming frequency from wavelength conversion
Driver size directly determines the frequency at which a woofer begins to beam: concentrating output in a narrowing cone rather than radiating broadly. The wavelength-to-Hz conversion calculates this beaming onset frequency from the driver's diameter. A 6.5-inch woofer measures approximately 0.165 meters across the cone. When the acoustic wavelength equals twice the cone diameter, beaming becomes significant: frequency = 343 ÷ 0.165 = 2078 Hz. Above 2 kHz, a 6.5-inch cone directs output forward in a narrowing pattern rather than dispersing broadly to off-axis listening positions.
Using the conversion to evaluate crossover frequency decisions
This calculation explains why crossover frequencies are not set arbitrarily: the handoff to a tweeter should occur before the woofer's directivity narrows enough to affect listeners at off-axis positions. Entering your woofer's diameter as the equivalent wavelength into the wavelength-to-Hz conversion gives the minimum recommended crossover frequency. If the published crossover is higher than this result, the woofer is already beaming at the crossover frequency. If the crossover is lower, the handoff happens before directivity narrows substantially, producing more uniform dispersion through the crossover range.4
A practical example: a 5.25-inch woofer (13.3 cm diameter) has a beaming onset at 343 ÷ 0.133 = 2579 Hz. Most 5.25-inch two-way designs cross over between 1.5 and 2.5 kHz, placing the handoff at or slightly below the beaming threshold. A 4-inch woofer (10 cm) beams at 3430 Hz, giving more crossover flexibility. If you are evaluating a speaker design and the crossover frequency exceeds the calculated beaming onset, the speaker will have narrow on-axis dispersion at the crossover, which may sound bright on-axis but thin off-axis. The sweep test at the crossover frequency from multiple listening angles reveals this effect directly.
Comparing bass trap positions using quarter-wavelength distances
Comparing two potential bass trap positions requires calculating which position targets the problem frequency most effectively. Bass traps absorb most efficiently at the quarter-wavelength distance from a room boundary, where particle velocity (which absorptive materials respond to) is highest. A 57 Hz room mode has a wavelength of 343 ÷ 57 = 6.02 meters. One quarter of that wavelength is 1.505 meters: placing a corner bass trap so its absorptive face is approximately 1.5 meters from the adjacent wall targets the 57 Hz mode where absorption efficiency is highest.
Identifying which room boundary to treat first
Not all room boundaries contribute equally to a specific mode. The axial mode for a room's length dimension produces a standing wave between the front and rear walls only, not between the side walls. Using the wavelength-to-Hz conversion to calculate which dimension produced the problem frequency tells you which pair of walls to treat first. A problem at 57 Hz in a room 3 meters wide (first width mode at 343 ÷ 6 = 57.2 Hz) calls for treatment near the side walls, not the front or rear walls, even if those walls are more accessible.
Verifying treatment effectiveness with the sweep after placement
After placing treatment at the calculated quarter-wavelength position, run the frequency sweep again at the problem frequency. A 2–3 dB reduction in perceived level at the treated mode frequency confirms the panel is positioned at an effective absorption point. A smaller reduction suggests the panel is at a pressure maximum rather than a particle velocity maximum, and shifting its position by a quarter-wavelength should improve absorption effectiveness.5
Try in the tool
Conversion covered by this page
0.343 Wavelength (m) converts to 1000 Hz using the formula on this page. Use this figure as a reference point alongside the tool below.
Verify with the Speaker Frequency Sweep & Resonance Tester tool.
Try it in the tool ↑- 1.
"Speed of sound," en.wikipedia.org, accessed June 2026. https://en.wikipedia.org/wiki/Speed_of_sound
- 2.
"Room modes," en.wikipedia.org, accessed June 2026. https://en.wikipedia.org/wiki/Room_modes
- 3.
Hugh Robjohns, "Q. What is a speaker's crossover frequency?," soundonsound.com, September 2020. https://www.soundonsound.com/sound-advice/q-what-speakers-crossover-frequency
- 4.
Paul White, "Practical Acoustic Treatment, Part 1," soundonsound.com, July 1998. https://www.soundonsound.com/techniques/practical-acoustic-treatment-part-1
- 5.
Rene Christensen, "Simulation Techniques: Room Gain," audioxpress.com, April 2024. https://audioxpress.com/article/simulation-techniques-room-gain
f = 343 ÷ 1 = 343 Hz. This frequency falls in the lower midrange, approximately two octaves above middle C (261.6 Hz). CapyToolkit's Speaker Sweep helps you hear whether those calculations match your actual listening position. At 343 Hz, wavelengths are short enough that nearby reflective surfaces create directional comb-filtering effects at close range, but still long enough that room modes are a factor in large rooms.
The first axial mode for a 3-meter ceiling height is f = 343 ÷ (3 × 2) = 343 ÷ 6 = 57.2 Hz. The ceiling-to-floor axial mode produces a pressure maximum at the floor and ceiling surfaces and a pressure minimum at room midheight. Subwoofers placed on the floor are at the pressure maximum for this mode, coupling efficiently to it.
λ = 343 ÷ 440 = 0.780 meters (78 cm). This means the acoustic wavelength of concert A is less than a meter, and it is short enough that nearby reflective surfaces create comb-filtering at audible frequencies, which is why close-mic placement on instruments affects the tonal quality of recordings.
Yes. The speed of sound varies by medium: approximately 343 m/s in air at 20°C, 1480 m/s in water, and 5000–6000 m/s in steel. The formula f = v ÷ λ uses the speed of sound in the relevant medium. For room acoustics and speaker testing, the air value (343 m/s) is always the applicable figure.
Square or near-square room cross-sections cause axial modes on both axes to cluster at the same frequency, creating a stronger and harder-to-treat resonance. A room 4 meters wide and 4.1 meters long has modes at approximately 42.9 Hz and 41.8 Hz respectively, which are close enough to reinforce each other and create a broader, more prominent bass buildup than either dimension alone would produce.
Convert Hz to Period (ms)
How to convert Hz to Period (ms)
To convert a frequency in Hz to its period (the duration of one complete cycle) in milliseconds, divide 1000 by the frequency: **T = 1000 ÷ f**. For example, a 100 Hz tone has a period of 1000 ÷ 100 = 10 milliseconds (each cycle completes in 10 ms). At 1 kHz, the period is 1000 ÷ 1000 = 1 millisecond. At 20 Hz, the period is 1000 ÷ 20 = 50 milliseconds. Period is the inverse of frequency: a longer period means lower frequency. This conversion is useful for audio delay settings, digital signal processing timing, and understanding the temporal resolution of the ear at different frequencies.1
Common Hz to Period (ms) conversions
Period, frequency, and audio delay settings
Use period length to reason about timing. The period of a frequency is the duration of one complete oscillation cycle. In audio engineering, understanding period length helps with delay-based processing decisions. A comb filter notch appears when a signal is mixed with a delayed copy of itself: the delay time equal to half the period produces a cancellation at the fundamental frequency and all even harmonics. For 80 Hz (period 12.5 ms), a delay of 6.25 ms produces a comb filter notch at 80 Hz. This is why setting digital reverb pre-delay, loudspeaker time alignment, and multi-speaker delay compensation requires knowing the period of the frequency range being corrected.2
Period and auditory masking in the bass range
Human hearing's ability to resolve timing differences between sounds (temporal resolution) is related to the period length at the frequency being resolved. At low frequencies (20–100 Hz), period lengths are long (50–10 ms), which means the ear has more time per cycle to evaluate each waveform. Long period lengths also mean that bass reflections and room echoes extend over many milliseconds, smearing attack transients in ways that are partially masked by the direct sound. Understanding period length explains why bass decay time in rooms (RT60) dominates bass quality perception more than impulse response timing precision. A 40 Hz tone with a 25 ms period gives the auditory system four complete waveform cycles within a single 100 ms integration window, making pitch detection at this frequency highly reliable even in reverberant conditions where higher-frequency detail is lost.3
Calculating speaker time alignment delays from period length
When two speakers in a system are at different distances from the listening position, their output arrives at different times. The period of a frequency at the crossover point determines the maximum delay error that produces destructive interference at that frequency. For a crossover at 80 Hz (period 12.5 ms), a time alignment error of one-quarter period (3.125 ms) rotates the phase 90 degrees and reduces the summed output at 80 Hz. Calculating the period for your crossover frequency gives you the alignment precision required to achieve flat summed output at the handoff point.
Converting period to a distance makes the requirement concrete. One millisecond of delay corresponds to approximately 34.3 cm of sound travel distance (343 m/s ÷ 1000). For an 80 Hz crossover (period 12.5 ms), a quarter-period delay of 3.125 ms corresponds to 3.125 × 34.3 = 107 cm of path length difference between the two speakers. A speaker alignment error of 50 cm at the 80 Hz crossover introduces a 1.46 ms delay, which equals approximately 42 degrees of phase rotation at 80 Hz, enough to produce a 3 dB summed output reduction at the crossover frequency.
Using period to set delay compensation in processor settings
Digital signal processors and AV receivers express time alignment as a delay in milliseconds or as a distance (which the processor converts to milliseconds internally). Convert your measured speaker-to-listening-position distances to milliseconds using the period relationship, then enter the delay compensation so that both speakers' arrival times match at the listening position. Confirming alignment by holding the sweep at the crossover frequency while switching the delayed speaker in and out reveals whether the summed output at the crossover point improves with the delay applied.4
Period length and audio delay settings for mixing and live sound
In recording and mixing, the Hz-to-period conversion directly informs reverb pre-delay settings. Pre-delay is the gap between a dry signal and the onset of reverberation. Setting it to a period length related to the reverb's content frequency creates a transparent reverb that masks itself behind the direct sound rather than cluttering it. For a reverb applied to vocals, which carry intelligibility information at 500 Hz to 4 kHz (periods of 0.25 to 2 ms), a pre-delay of one full period at 500 Hz (2 ms) adds a gap before the reverb onset that allows the initial consonant attack to reach the listener clearly before the reverb begins.
Applying period-based pre-delay to bass reverb and room simulation
For room simulation applied to kick drum or bass content centred around 80–200 Hz, pre-delay values of 5–12 ms (corresponding to one period at 200 Hz through one period at 80 Hz) place the reverb onset at a musically coherent interval relative to the low-frequency content. A pre-delay shorter than one period at the content's fundamental frequency produces early reflections that partially cancel the direct signal during the first cycle, creating a thin, coloured quality. Calculating the period for the frequency range of the signal and using it as the minimum pre-delay eliminates this early-reflection coloration.
When using algorithmic reverb on a full mix, the bass content period still matters for overall coherence. A pre-delay set to one period at 80 Hz (12.5 ms) works well for a mix with significant low-end content, as it allows the fundamental bass cycles to complete before the reverb tail begins. However, if the mix is sparse or lacks strong sub-bass, a shorter pre-delay based on a higher frequency (e.g., one period at 500 Hz = 2 ms) can create a tighter, more present sound without the perceived distance that a longer pre-delay introduces. Matching pre-delay to the dominant frequency range of the programme material, using the Hz-to-period conversion as a guide, produces more natural results than using a fixed pre-delay value across all material.
Using period calculations for multi-speaker delay compensation in live sound
In live sound reinforcement, distributed speaker systems require time alignment to avoid comb filtering at the crossover distance. The delay tower must be offset by exactly the travel time between the main speakers and the delay tower position. Calculating the period of the crossover frequency between systems confirms the alignment precision required: for a 4 kHz crossover (period 0.25 ms), time alignment must be accurate within 0.0625 ms (one-quarter period) to avoid a 3 dB summation error. At 200 Hz (period 5 ms), the same quarter-period precision requires alignment within 1.25 ms, which is achievable with the delay settings on most digital processors.5
Try in the tool
Conversion covered by this page
100 Hz converts to 10 Period (ms) using the formula on this page. Use this figure as a reference point alongside the tool below.
Verify with the Speaker Frequency Sweep & Resonance Tester tool.
Try it in the tool ↑- 1.
"Frequency," en.wikipedia.org, accessed June 2026. https://en.wikipedia.org/wiki/Frequency
- 2.
"Comb filter," en.wikipedia.org, accessed June 2026. https://en.wikipedia.org/wiki/Comb_filter
- 3.
Paul White, "Practical Acoustic Treatment, Part 1," soundonsound.com, July 1998. https://www.soundonsound.com/techniques/practical-acoustic-treatment-part-1
- 4.
Rene Christensen, "Simulation Techniques: Room Gain," audioxpress.com, April 2024. https://audioxpress.com/article/simulation-techniques-room-gain
- 5.
Sam Inglis, "Reverb: What Do All Those Knobs Do?," soundonsound.com, May 2020. https://www.soundonsound.com/techniques/reverb-what-do-all-those-knobs-do
T = 1000 ÷ 80 = 12.5 milliseconds. Each cycle of the 80 Hz tone takes 12.5 ms to complete. CapyToolkit's Speaker Sweep helps you hear how those phase relationships affect the summed bass at your listening position. A speaker that is 12.5 ms later in time alignment relative to another speaker will add to the 80 Hz output from the first speaker in some positions and cancel it in others, which is the time alignment problem that subwoofer phase controls address.
The phase control on a subwoofer rotates the signal relative to the main speakers. A 90° phase rotation equals a delay of one-quarter period. At 80 Hz (period 12.5 ms), a 90° rotation corresponds to a 3.125 ms delay. Setting phase so that the subwoofer's output adds constructively with the main speakers at the crossover frequency requires matching the period at the crossover point.
A notch at 100 Hz requires a delay equal to half the period: T = 1000 ÷ 100 = 10 ms; half-period = 5 ms. Mixing a signal with a 5 ms delayed copy of itself produces cancellation at 100 Hz (and all odd multiples: 300 Hz, 500 Hz, etc.). This is the basis of comb filtering, which is the audio artifact that occurs when a speaker's direct sound mixes with a single strong room reflection at approximately the same level.
Samples are discrete time steps at the audio sample rate. At 44.1 kHz sample rate, one sample is 1000 ÷ 44100 ≈ 0.0227 ms. To convert a delay in milliseconds to samples at 44.1 kHz: multiply the millisecond value by 44.1. A 5 ms delay at 44.1 kHz is 5 × 44.1 = 220.5 samples. At 48 kHz (broadcast standard), one sample is 1000 ÷ 48000 ≈ 0.0208 ms, so 5 ms = 5 × 48 = 240 samples.
The auditory system can resolve timing differences between repeated sound events down to approximately 2–4 milliseconds for simple stimuli in ideal conditions. This corresponds to a frequency of 250–500 Hz (T = 1000/f). The practical limit for auditory event perception, which is the basis for the Haas effect and early reflection masking in room acoustics, is approximately 30–50 ms at typical listening levels.